5/29/2018 · Ex 12.3, 12 In figure, OACB is a quadrant of a circle with centre O and radius 3.5 cm. If OD = 2 cm, find the area of the quadrant OACB, It is given that, OACB is a quadrant Given radius = 3.5 cm We know that Area of Quadrant OACB = 1/4 Area of a circle Area of quadrant OACB = 1/4 2 = 1/4 22/7 (3.5)2 = 1/4 22/7 3.5 3.5 = 3.625 cm2 …
In the given figure, OACB is a quadrant of a circle with centre O and radius 3.5 cm. If OD = 2 cm, find the area of the shaded region. Since OACB is a quadrant, it will subtend 90° angles at O.
8/3/2018 · In the given figure, OACB is a quadrant of circle with centre O and radius 3.5 cm. If OD = 2 cm, find the area of the [Use ? = 22/7] (i) Quadrant OACB. (ii) Shaded region. areas related to circles.
OACB is a quadrant of a circle with centre O and its radius is 3.5cm . If `OD=2cm`, find the area of (i) area quadrant OACB (ii) the shaded region. [Take `pi=22/7`], In the figure alongside, OACB is a quadrant of a circle. The radius OA = 3.5 cm and OD = 2 cm. Calculate the area of the shaded portion (Take ? = 22/7) Solution.
In the Following Figure, Oacb is a Quadrant of a Circle with Centre O and Radius 3.5 Cm. If Od = 2 Cm, Find the Area of the (I) Quadrant Oacb (Ii) Shaded Region.
(i) Since OACB is a quadrant, it will subtend 90° angle at O. Area of quadrant OACB (ii) Area of ?OBD Area of the shaded region = Area of quadrant OACB ? Area of ?OBD, 6/11/2018 · In the figure, OABC is a square of side 7 cm. If OAPC is a quadrant of a cirice with centre O, then find the area of the shaded region. (Use ? = 22/7) [CBSE 2012] Solution: In square OABC, whose side is 7 cm, OAPC is a quadrant Area of square = (side)² = (7)² = 49 cm² and radius of quadrant = 7 cm. Question 22. In the figure, OE = 20 cm.
